Evaluate g(x) at points close to the discontinuity:
Lim x-> -3- g(x) = -3
g(-3)=5(-3)/((-3)^2-4(-3))
=-15/21
=-5/7
So there is a jump from -3 on the left to -5/7 on the right.
Can you suggest what kind of discontinuity it is?
Find the discontinuities of the given function. Classify them as a point discontinuity or a jump discontunuity.
g(x)= x, x<-3
5x/(x^2-4x), x>= -3
3 answers
I assume it's a jump since it jumps from one value to another.
That is correct.
If you do not have clear definitions of each type of discontinuity, you can check the following link:
http://en.wikipedia.org/wiki/Classification_of_discontinuities
If you do not have clear definitions of each type of discontinuity, you can check the following link:
http://en.wikipedia.org/wiki/Classification_of_discontinuities