Find the dimensions. The length is 200 feet more than the width, and the perimeter is 1,040 feet. Find the length and width, use the perimeter formula P= 2L +2W

Answer 1

Let's use the given information to set up two equations.

1. "The length is 200 feet more than the width" can be written as:

L = W + 200

2. "the perimeter is 1,040 feet" can be written using the formula:

P = 2L + 2W

Substituting equation 1 into equation 2, we get:

P = 2(W + 200) + 2W

Simplifying the equation:

1,040 = 4W + 400

Subtracting 400 from both sides:

640 = 4W

Dividing both sides by 4:

W = 160

Now we can use equation 1 to find the length:

L = 160 + 200 = 360

Therefore, the dimensions of the rectangle are:

Width = 160 feet
Length = 360 feet

Answer 2

The bot's solution is much too lengthy and cumbersome.

let the width be x ft
then the length = x+200 ft

2x + 2(x+200) = 1040
4x + 400 = 1040
4x = 640
x = 160

so the width is 160 ft, and the length is 360 ft