If πr^2h=V then h=V/(πr^2)
the area is thus
a = 2πr^2+2πrh = 2πr^2+2πrV/(πr^2)
= 2πr^2 + 2V/r
minimize that
Find the dimensions (in units) of the closed cylinder with volume
V = 16π
units3 that has the least amount of surface area.
radius
units
height
units
1 answer