Find the dimensions (in units) of the closed cylinder with volume

V = 16π
units3 that has the least amount of surface area.
radius
units
height
units

1 answer

If πr^2h=V then h=V/(πr^2)
the area is thus

a = 2πr^2+2πrh = 2πr^2+2πrV/(πr^2)
= 2πr^2 + 2V/r

minimize that
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