Find the dimension of the following

I. Impulse
ii. Angular velocity
iii. moment of force
IV. Frequency

1 answer

To find the dimensions of physical quantities, we use the basic dimensions of mass \([M]\), length \([L]\), and time \([T]\). Let's analyze each quantity.

I. Impulse

Impulse is defined as the change in momentum of an object when a force is applied over a period of time. It can be expressed as:

\[ \text{Impulse} = \text{Force} \times \text{Time} \]

The dimension of force is given by:

\[ \text{Force} = \text{mass} \times \text{acceleration} = [M][LT^{-2}] = [MLT^{-2}] \]

Thus, the dimension of impulse is:

\[ [\text{Impulse}] = [MLT^{-2}] \times [T] = [MLT^{-1}] \]

II. Angular Velocity

Angular velocity is defined as the rate of change of angular displacement with respect to time. Its dimension can be expressed as:

\[ \text{Angular Velocity} = \frac{\text{Angle}}{\text{Time}} \]

The dimension of angle (radians) is dimensionless, so we have:

\[ [\text{Angular Velocity}] = [T^{-1}] \]

III. Moment of Force

The moment of force (or torque) is defined as the product of the force and the perpendicular distance from the axis of rotation:

\[ \text{Moment of Force} = \text{Force} \times \text{Distance} \]

As we have established earlier, the dimension of force is \([MLT^{-2}]\), and the dimension of distance is \([L]\). Therefore, the dimension of the moment of force is:

\[ [\text{Moment of Force}] = [MLT^{-2}] \times [L] = [ML^2T^{-2}] \]

IV. Frequency

Frequency is defined as the number of occurrences of a repeating event per unit time. The dimension can be expressed as:

\[ \text{Frequency} = \frac{1}{\text{Time}} = [T^{-1}] \]

Summary of Dimensions

  • Impulse: \([MLT^{-1}]\)
  • Angular Velocity: \([T^{-1}]\)
  • Moment of Force: \([ML^2T^{-2}]\)
  • Frequency: \([T^{-1}]\)