Find the dilation of 2 for the given shape centered at the origin

a=(1-4)
b=(1-1)
c=(3-1)
d(3-4)

1 answer

To find the dilation of a shape centered at the origin by a factor of 2, you multiply each coordinate of the shape by the dilation factor (which is 2 in this case).

Given the points:

  • \( a = (1, -4) \)
  • \( b = (1, -1) \)
  • \( c = (3, -1) \)
  • \( d = (3, -4) \)

We will apply the dilation transformation to each point.

Dilation by a factor of 2:

  1. For point \( a = (1, -4) \): \[ a' = (2 \times 1, 2 \times -4) = (2, -8) \]

  2. For point \( b = (1, -1) \): \[ b' = (2 \times 1, 2 \times -1) = (2, -2) \]

  3. For point \( c = (3, -1) \): \[ c' = (2 \times 3, 2 \times -1) = (6, -2) \]

  4. For point \( d = (3, -4) \): \[ d' = (2 \times 3, 2 \times -4) = (6, -8) \]

The new points after dilation are:

  • \( a' = (2, -8) \)
  • \( b' = (2, -2) \)
  • \( c' = (6, -2) \)
  • \( d' = (6, -8) \)

So, the coordinates of the dilated shape are:

  • \( a'(2, -8) \)
  • \( b'(2, -2) \)
  • \( c'(6, -2) \)
  • \( d'(6, -8) \)