y(x)=c^x+x^c
=y'(x)=x*c+2x
=y'(x)=cx+2x
Find the derivative of the function y(x)=c^x+x^c. Assume that c is a constant.
2 answers
We have c^x, not c*x
y' = c^x ln c + cx^(c-1)
= c^x (ln c + c/x)
y' = c^x ln c + cx^(c-1)
= c^x (ln c + c/x)