Find the derivative of h(x)=7lnx^4
h'(x)=???
5 answers
is it 24x^3/x^4??
I mean 28x^3/x^4
let z = x^4 so dz/dx = 4 x^3
then
y = 7 ln z
dy/dz = 7/z
dy/dx = dy/dz dx/dx = (7/z)(4 x^3)
= 28 (x^3/x^4)
= 28/x
then
y = 7 ln z
dy/dz = 7/z
dy/dx = dy/dz dx/dx = (7/z)(4 x^3)
= 28 (x^3/x^4)
= 28/x
Calculus I mean.
you could also notice that
ln(x^4) = 4 lnx
so,
y = 7*4 lnx = 28 lnx
dy/dx = 28/x
ln(x^4) = 4 lnx
so,
y = 7*4 lnx = 28 lnx
dy/dx = 28/x