Asked by Nuru
Find the derivative for the following:
a. y = x^2 e^x
b. y = (e^x + 2)^3/2
c. y = e^-3x
d. y = (e^x-e^-x)/2
a. y = x^2 e^x
b. y = (e^x + 2)^3/2
c. y = e^-3x
d. y = (e^x-e^-x)/2
Answers
Answered by
Reiny
a) (product rule)
y' = x^2 e^x + 2x e^x
= x e^x( x +2)
b) (chain rule)
y' = (3/2)(e^x + 2)^(1/2) (e^x)
= (3/2) e^x (e^x + 2)^(1/2)
c) y' = -3 e^(-3x)
d)
y = (1/2) e^x - (1/2) e^-x
y' = .....
give it a try, it is straightforward from here
y' = x^2 e^x + 2x e^x
= x e^x( x +2)
b) (chain rule)
y' = (3/2)(e^x + 2)^(1/2) (e^x)
= (3/2) e^x (e^x + 2)^(1/2)
c) y' = -3 e^(-3x)
d)
y = (1/2) e^x - (1/2) e^-x
y' = .....
give it a try, it is straightforward from here
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