Find the derivative for k(x) = (5x4 + 2)(3sin x).

Would this be the answer:

(60sinx)x^3+ (15cosx)x^5+ 2

3 answers

No.
Use the product rule
d/dx(u*v) = u dv/dx + v du/dx
and let 5x^4 +2 = u(x), and
3 sin x = v(x)
du/dx = 20 x^3
dv/dx = 3 cos x

Derivative = 3 cos x *(5x^4 + 2)
+ 3 sin x *(20 x^3)
That is how I got my answer, by using product rule.
Obviously you made a mislake somewhere along the line. If you care to show your steps, someone will show you where the error was made.
Similar Questions
  1. Find the derivative of y with respect to x:y=3sin^4(2-x)^-1 y=[3sin(2-x)^-1]^4 y'=4[3sin(2-x)^-1]^3 (-3cos(2-x)^-1)(-1)
    1. answers icon 0 answers
  2. find the maximum value off(x)= 3cos(x)-2sin(x) I know you have to take the derivative but after the derivative I don't know how
    1. answers icon 1 answer
  3. find the maximum value off(x)= 3cos(x)-2sin(x) I know you have to take the derivative but after the derivative I don't know how
    1. answers icon 1 answer
    1. answers icon 1 answer
more similar questions