Find the derivative dy/dx

y=e^(sinh(x))

1 answer

just use the good old chain rule. By now that shouldn't be causing any difficulties, eh?

If y = e^u, y' = e^u u'

y = e^(sinh(x))
y' = e^sinh(x)) * cosh(x)
Similar Questions
  1. 1.)Find dy/dx when y= Ln (sinh 2x)my answer >> 2coth 2x. 2.)Find dy/dx when sinh 3y=cos 2x A.-2 sin 2x B.-2 sin 2x / sinh 3y
    1. answers icon 2 answers
    1. answers icon 1 answer
    1. answers icon 0 answers
    1. answers icon 3 answers
more similar questions