These are standard formulas...
f()= 1/u
f'=-u'/u^2 where u is sqrt(8t-3), u'=4/sqrt( )
g= u/v
g'=-uv'/v^2 + u'/v where u=(4t-3)^2 v=(5t+1)^4
I assume you can do it from here.
Find the derivative.
11) f(t)=(1)/(sqrt(8t-3))
12) g(t)= ((4t-3)^2)/ ((5t+1)^4)
Thanks.
1 answer