To find the cubic root of 96, we write this as:
\[ \sqrt[3]{96} \]
To simplify \( \sqrt[3]{96} \), we can factor 96 into its prime factors:
\[ 96 = 2^5 \times 3^1 \]
Now we can apply the cube root to these factors:
\[ \sqrt[3]{96} = \sqrt[3]{2^5 \times 3^1} = \sqrt[3]{2^5} \times \sqrt[3]{3^1} \]
Next, we simplify each term:
- \(\sqrt[3]{2^5} = 2^{5/3} = 2^{1 + 2/3} = 2 \times 2^{2/3}\), which can be written as \(2 \sqrt[3]{4}\).
- \(\sqrt[3]{3^1} = 3^{1/3} = \sqrt[3]{3}\).
Combining these, we get:
\[ \sqrt[3]{96} = 2 \sqrt[3]{4} \times \sqrt[3]{3} = 2 \sqrt[3]{12} \]
Thus, the cubic root of 96 can be expressed as:
\[ \sqrt[3]{96} = 2 \sqrt[3]{12} \]
Out of the given responses, the closest match is:
\[ 2 \sqrt[3]{12} \]
This is the answer.