To find the critical value \( z_{\alpha/2} \) for a confidence level of 99.5%, we need to determine the value that corresponds to the tails of the standard normal distribution.
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Identify the significance level:
- A confidence level of 99.5% has a significance level \( \alpha = 1 - 0.995 = 0.005 \).
- Since \( z_{\alpha/2} \) represents the critical value for the upper tail of the standard normal distribution, we need to find \( \alpha/2 \): \[ \alpha/2 = 0.005 / 2 = 0.0025 \]
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Find the critical z-value:
- We are looking for the z-value such that the area to the right of it is 0.0025. This is equivalent to finding the z-value that leaves 0.9975 to the left: \[ P(Z < z_{\alpha/2}) = 0.9975 \]
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Using the standard normal distribution table or calculator:
- Using a standard normal distribution table or an inverse normal calculator, we look for the z-value that corresponds to 0.9975.
- This value is typically found to be approximately \( z_{0.0025} \approx 2.576 \).
Therefore, the critical value \( z_{\alpha/2} \) needed to construct a confidence interval with a confidence level of 99.5% is: \[ z_{\alpha/2} \approx 2.576 \]