h' = 3/4 t^-1/4 - 3/4 t^-3/4
= 3/4 t^-3/4 (t^1/2 - 1)
so, when is h' = 0?
Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.)
h(t) = t^(3/4) − 3t^(1/4)
1 answer