Find the coordinates of the vertex of the parabola:y=x^2-8x+2

Answer 1

Well, this one is less trivial so I will show you how to complete the square
x^2 - 8 x + 2 = y

x^2 - 8 x = y - 2

(half of 8) squared = 16

x^2 - 8 x + 16 = y + 14

(x-4)^2 = (y+14)
so
(4, -14)