Find the coordinates of the vertex of the graph of f(x)=2x^2+10x-17.

Answer 1

find the zeroes:

2x^2+10x-17=0

x= (-10+-sqrt(100+136))/4

x= (-2.5+-3.84)

x= -6.34; 1.34

so halfway between those is the vertex,or at -2.5