Find the coordinates of the vertex and the equation of the axis of symmetry of the parabola given by the equation.

Question

x = −1/3y^2+4

vertex
(x, y) =



axis of symmetry

Sketch the graph.

Answer 1

recall that the vertex of

x-h = a(y-k)^2

is at (h,k). Look at your function and you see that

x-4 = -1/3 (y-0)^2

so the vertex is at (4,0)

Now use your knowledge that the vertex lies on the axis of symmetry, and you're almost home free.