y = 8(x^2+6x) - 3
now just complete the square.
y = 8(x^2+6x+9) - 3
but wait. You just added 8*9, so subtract it off so things don't get changed.
y = 8(x^2+6x+9) - 3 - 8*9
y = 8(x+3)^2 - 75
now it's easy to see that the vertex is at (-3,-75), and of course, it lies on the axis of symmetry.
Find the coordinates of the vertex and the equation of the axis of symmetry of the parabola with the given equation.
y = 8x^2 + 48x − 3
vertex
(x, y) =
axis of symmetry ________
1 answer