Find the coordinates of the turning point whose equation is y=x^2 - 4x +1

Answer 1

recall that the vertex of ax^2+bx+c is at x = -b/2a
so the turning point is at (2,-3)

or, complete the square
x^2-4x+1 = x^3-4x+4 - 3 = (x-2)^2 - 3
so the vertex is at (2,-3)