reflect through x=3: (x,y)->(3-(x-3),y) = (6-x,y)
reflect through y=x: (x,y)->(y,x)
so, now just combine those two transformations:
(x,y)->(6-x,y)->(y,6-x)
Find the coordinates of the image of the point p(4,6)under the reflection about the line x=3 followed by the reflection about the line y=x.
1 answer