the major axis is vertical, so we have
center: (0,0)
a=13, b=12
c^2 = a^2-b^2, so c=5
vertices: (0,±13)
covertices: (±12,0)
foci: (0,±5)
eccentricity e = c/a = 5/13
length of latus rectum is 2b^2/a = 2*144/13, so the latera recti are the lines through the foci with ends at
(±144/13,5) and (±144/13,-5)
http://www.wolframalpha.com/input/?i=ellipse+y^2%2F169+%2B+x^2%2F144+%3D1
Find the coordinates of the foci, the ends of major and minor axis, the ends of latus rectum then sketch the graph of y^2/169 + x^2/144 =1
(i need the anwers to that i will have an idea on how to solve the remaining .)
1 answer
1 answer