To find the centroid of a triangle, we take the average of the x-coordinates of the three vertices and the average of the y-coordinates of the three vertices.
The x-coordinate of the centroid is given by:
(x-coordinate of centroid) = (x-coordinate of P + x-coordinate of Q + x-coordinate of R)/3
= (-6 + (-2) + 8)/3
= 0/3
= 0
The y-coordinate of the centroid is given by:
(y-coordinate of centroid) = (y-coordinate of P + y-coordinate of Q + y-coordinate of R)/3
= (1 + (-5) + 1)/3
= -3/3
= -1
Therefore, the coordinates of the centroid of the triangle are (0, -1).
Find the coordinates of the centroid of a triangle whose vertices are P(-6,1), Q(-2,-5) and R(8,1).
1 answer