find the coordinates of point P that lies on the line segment MQ, M(5,-2), Q(-2,12), and partitions the segment at a ratio of 2:5

Answer 1

MP is 2/7 of the way from M to Q
The distance from M to Q is Q-M
So, P = M + 2/7 (Q-M)
Thus, the x-coordinate of P is
x = 5 + 2/7 (-2-5) = 5 - 2 = 3
and y = -2 + 2/7 (12+2) = -2+4 = 2
P = (3,2)

Answer 2

Point P lies on Line Segment NM. Point N is located at (- 2, - 6) and Point Mis located at * (5, 8), 1f; NP / P * M = 5/2 (the line partitions in a 5:2 ratio) . Where is point P located on Line NM?*