To find the coordinates of point C' after dilating triangle ABC by a scale factor of 2 with the center of dilation at the origin (0,0), we can use the following formula for dilation:
If \( (x, y) \) are the coordinates of a point before dilation, then the coordinates after dilation will be given by:
\[ (x', y') = (kx, ky) \]
where \( k \) is the scale factor.
For triangle ABC:
- Coordinate A is \( (0,0) \)
- Coordinate B is \( (1,-3) \)
- Coordinate C is \( (3,0) \)
Since we are only interested in point C (which has coordinates \( (3,0) \)), we will apply the dilation to C:
- Scale factor \( k = 2 \)
- Original coordinates of point C: \( (3, 0) \)
Now applying the dilation formula: \[ C' = (2 \cdot 3, 2 \cdot 0) = (6, 0) \]
So, the coordinates of point C' are \( (6, 0) \).
The final answer is: \[ \boxed{(6, 0)} \]