Find the concentration of OH- of a solution of 45.0mL of 0.0921 M Ba(OH)2 diluted with enough water to make 350.0 mL of solution.

1 answer

M Ba(OH)2 solution = 0.0921 x (45.0/350.0) = ? M

Ba(OH)2 is a strong base (ionizes 100%) to concn Ba(OH)2 is ?M from above.
Then (OH^-) - twice that of the base since there are two OH ions per molecule of Ba(OH)2.