Find the compound amount compound interest resulting from the investment of Birr 1000 at 6% for 10 years,

Compounded annually.
Compounded semiannually.
Compounded quarterly.
Compounded monthly.
Compounded continuously.

1 answer

To find the compound amount and compound interest resulting from the investment of Birr 1000 at an interest rate of 6% for 10 years, we will apply the formulas for compound interest under different compounding frequencies:

  1. Compounded Annually: \[ A = P(1 + r/n)^{nt} \] Where:

    • \(A\) = the amount of money accumulated after n years, including interest.
    • \(P\) = principal amount (the initial amount of money, which is Birr 1000).
    • \(r\) = annual interest rate (decimal) (6% = 0.06).
    • \(n\) = number of times that interest is compounded per year (1 for annual).
    • \(t\) = number of years the money is invested for (10 years).

    Plugging in the values: \[ A = 1000 \left(1 + \frac{0.06}{1}\right)^{1 \times 10} = 1000(1.06)^{10} \approx 1000 \times 1.79085 \approx 1790.85 \] Compound interest = \(A - P = 1790.85 - 1000 = 790.85\)

  2. Compounded Semiannually: Here \(n = 2\): \[ A = 1000 \left(1 + \frac{0.06}{2}\right)^{2 \times 10} = 1000(1 + 0.03)^{20} = 1000(1.03)^{20} \approx 1000 \times 1.80611 \approx 1806.11 \] Compound interest = \(A - P = 1806.11 - 1000 = 806.11\)

  3. Compounded Quarterly: Here \(n = 4\): \[ A = 1000 \left(1 + \frac{0.06}{4}\right)^{4 \times 10} = 1000(1 + 0.015)^{40} = 1000(1.015)^{40} \approx 1000 \times 1.80611 \approx 1810.51 \] Compound interest = \(A - P = 1810.51 - 1000 = 810.51\)

  4. Compounded Monthly: Here \(n = 12\): \[ A = 1000 \left(1 + \frac{0.06}{12}\right)^{12 \times 10} = 1000(1 + 0.005)^{120} = 1000(1.005)^{120} \approx 1000 \times 1.81940 \approx 1819.40 \] Compound interest = \(A - P = 1819.40 - 1000 = 819.40\)

  5. Compounded Continuously: The formula for continuous compounding is: \[ A = Pe^{rt} \] Where \(e\) is the base of the natural logarithm (approximately 2.71828). \[ A = 1000 e^{0.06 \times 10} = 1000 e^{0.6} \approx 1000 \times 1.82212 \approx 1822.12 \] Compound interest = \(A - P = 1822.12 - 1000 = 822.12\)

Summary:

  • Compounded Annually:
    • Amount: Birr 1790.85, Interest: Birr 790.85
  • Compounded Semiannually:
    • Amount: Birr 1806.11, Interest: Birr 806.11
  • Compounded Quarterly:
    • Amount: Birr 1810.51, Interest: Birr 810.51
  • Compounded Monthly:
    • Amount: Birr 1819.40, Interest: Birr 819.40
  • Compounded Continuously:
    • Amount: Birr 1822.12, Interest: Birr 822.12