If z = a+bi, we have
(1+i)(a+bi) - 2(a-bi) = -11+25i
Expand all that out and you get
(-a-b)+(a+3b)i = -11+25i
So, that means that
-a-b = -11
a+3b = 25
a=4
b=7
So, z = 4+7i
Find the complex number z that satisfies (1 + i)z - 2 overline{z} = -11 + 25i.
Im not sure how to solve this. I tried distributing the z out first but im still confused on this problem.
1 answer