Find the change of the mechanical energy of a 1000-kg car traveled down an incline with 1:10 grade a total distance of 100 m during which its speed increased from 10 m/s to 20 m/s?
Is my answer correct, if not what did I do wrong?
ME=KE+PE+Q
KE=[.5*1000*20^2]- [.5*1000*10^2]
KE=200000 - 50000 = 150000
PE=[1000*9.8*10]-[1000*9.8*0]
PE=9800
150000+9800 = 248000J
2 answers
the kinetic energy increased but the potential energy DECREASED
1000 * 9.8 * 10 = 98,000