Find the biggest value of c that satisfy the Mean Value Theorem for integrals for

f(x)= 1/(x+1)^6 on the interval [0,7]

1 answer

the slope of the secant is (1/8^6 - 1)/7 ≈ -1/7

f' = -6/(x+1)^7
so, you want

-6/(c+1)^7 = -1/7
c ≈ 0.7
c is in the interval

Since f is monotonically decreasing, there is no other value for c.