Find the bearing and airspeed for a plane to fly 630 miles due north in 3 hours if the wind is blowing from a direction of 318* and is blowing at 15mph. Approximate the bearing to the nearest degree and the speed to the nearest mile per hour.

Answer 1

Vpw = 630mi/3h = 210m1/h, Due North

Vpw = Vp + Vw = 210i
Vp + 15[318o] = 210i
Vp + 15*Cos318+15*sin318 = 210i
Vp + 11.15 -10i = 210i
Vp = -11.15 + 210i + 10i = -11.15 + 220i
,Q2.

Tan A = 220/-11.15 = -19.73094
A = -87.1o = 87.1o N. of W. = 92.9o CCW
from + x-axis. = 2.9o W. of N. = Direction.

Vp = 220/sin92.9 = 220.3 mi/h