To find the balance after 10 years of a $30,000 savings account that pays 10% interest compounded yearly, use the formula for compound interest:
A = P(1 + r/n)^(nt)
Where:
A = the future balance
P = the principal amount (initial deposit)
r = annual interest rate (as a decimal)
n = number of times interest is compounded per year
t = number of years
In this case, the principal amount (P) is $30,000, the annual interest rate (r) is 10% (0.10 as a decimal), the interest is compounded yearly (n = 1), and the time period (t) is 10 years.
Substituting these values into the formula:
A = 30000(1 + 0.10/1)^(1*10)
A = 30000(1 + 0.10)^(10)
A = 30000(1.10)^(10)
A = 30000(2.5937)
A = $77,811
Therefore, the balance after 10 years will be $77,811.
find the balance after 10 years of a $30,000 savings account
that pays 10% interest compounded yearly.
1 answer