for y=ax^2+bx+c, vertex is at x = -b/2a
if you complete the square, and have
(y-k) = a(x-h)^2 then
the vertex is at (h,k)
the axis of symmetry goes through the vertex.
the sign of the x^2 term determines whether the vertex is a min or max.
So, what do you come up with?
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1 answer
1 answer