find the axis of symmetry f(x)=-2x2-12x+8find the axis of symmetry f(x)=-2x2-12x+8

Answer 1

f(x)=2(x^2-6x+4)=2(x^2-6x+9-5)=
=2((x-3)^2-5)=2(x-3)^2-10
The vertical axis x=3