you are looking at dividing the definite integral of f(x) from 0 to 5 by the length of the interval, namely (5-0)=5.
∫(1/5)exdx
=(1/5)[ex] from 0 to 5
=(1/5)(e5-e0)
=(1/5)(148.413-1)
=29.483
The average over the interval
=29.483/5
=5.8965
Find the average value of the function on the given interval:
f(x) = e^x/5, [0,5]
1 answer