Find the average rate of change of the function f(x) = 2x4 +
3x2 ¡ x + 2:
(a) on the interval [0; 3]
and
(b) on the interval [¡2; 0]
4 answers
Any help would be great. i am so confused
f(x)=2x4+3x²-x+2
(please check, because one of the characters posted in the function is not legible).
The rate of change on the interval [a,b]
is given by the change in f(x) divided by the change in x, i.e.
average rate of change on the interval [a,b], Δf(x)/Δx
=(f(b)-f(a))/(b-a) where b≠a.
Give it a try and post your answer for checking if you wish.
(please check, because one of the characters posted in the function is not legible).
The rate of change on the interval [a,b]
is given by the change in f(x) divided by the change in x, i.e.
average rate of change on the interval [a,b], Δf(x)/Δx
=(f(b)-f(a))/(b-a) where b≠a.
Give it a try and post your answer for checking if you wish.
Thank you so much. I think i got this one. Calculus is hard.
It's the beginning of the term, and almost everything is hard at the beginning. Once you get the handle of it, it will be fun.