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Find the average rate of change in height of the orange from t=2 to t=5 (in feet per second)

The equation is h (t)=605+15t-4.9t^2 in feet.

I know the the average rate of change is change in q/ change in time. Do I put t=3 and subtract the quantity of 5 and 2 in the formula for the top?

1 answer

h(5)-h(2)
-------------- = ?
5-2
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