6x^2 - 12 x -90 = 38 ??? assuming your 38 is correct
6 x^2 - 12 x - 128 = 0
3x^2 - 6 x - 64 = 0
x =5.73
Find the average or mean slope of 2x^3 - 6x^2 - 90x +3 on the interval [-6,10]?
By the Mean Value Theorem, we know there exists at least one c in the open interval ( -6 , 10 ) such that f'( c) is equal to this mean slope.
::>> I already found the mean slope of the function which is 38. Now I'm trying to find "c". I can't get c.
1 answer
1 answer