find the area of the triangle formed by P1(-2, 2pi/3) P2(2, 4pi/3) and the pole

3 answers

The area of the triangle is 8√3.

To find the area, use the formula A = 1/2 * |x1*y2 - x2*y1|, where x1 and y1 are the coordinates of point P1, and x2 and y2 are the coordinates of point P2.

A = 1/2 * |(-2)*(4π/3) - (2)*(2π/3)|
A = 1/2 * |(-8π/3) - (4π/3)|
A = 1/2 * |-12π/3|
A = 8√3
hello
AAAaannndd the bot gets it wrong yet again!
and with a solution so different from the previous posting. ??
still √3