Find the area of the triangle ABC given A = 30°, b = 5, and c = 2.

Answer 1

Use the law of cosines to find side a.

a^2=b^2+c^2 -2bcCosA

Then area= sqrt [s(s-a)(s-b)(s-c)]

where s is half the perimeter.

There are about 100 other ways to work this.