Use the law of cosines to find side a.
a^2=b^2+c^2 -2bcCosA
Then area= sqrt [s(s-a)(s-b)(s-c)]
where s is half the perimeter.
There are about 100 other ways to work this.
Find the area of the triangle ABC given A = 30°, b = 5, and c = 2.
1 answer