To find the area of a trapezoid, you can use the formula:
\[ \text{Area} = \frac{(b_1 + b_2)}{2} \times h \]
where \( b_1 \) and \( b_2 \) are the lengths of the two bases, and \( h \) is the height.
In your case:
- \( b_1 = 4 , \text{ft} \)
- \( b_2 = 10 , \text{ft} \)
- \( h = 8 , \text{ft} \)
Now, plug in the values:
\[ \text{Area} = \frac{(4 + 10)}{2} \times 8 \]
Calculating the sum of the bases:
\[ (4 + 10) = 14 \]
Then, divide by 2:
\[ \frac{14}{2} = 7 \]
Now multiply by the height:
\[ \text{Area} = 7 \times 8 = 56 , \text{ft}² \]
So, the area of the trapezoid is \( 56 , \text{ft}² \).
The correct answer is C. 56ft².