It will help to draw a figure.
I did, and it looks to me like the line theta = pi is NOT a bounding curve. The enclosed area is between the theta = 1.5 line and the spiral cruve r = 2 theta.
For the area, integrate
(1/2) r^2 d theta
= (1/2) 4 theta^2 dtheta
from theta = 0 to theta = 1.5 pi
I get the indefinite interal to be (2/3)(theta)^3
The definite integral is then
(2/3)(3 pi/2)^3
= (9/4) pi^3
Find the area of the region which is bounded by the polar curves
theta =pi and
r=2theta 0<theta<1.5pi inclusive
3 answers
The answer is not correct, please try again.
I got it, u have to
integrate (1/2) 4 theta^2 dtheta
from theta=0 to theta=pi
integrate (1/2) 4 theta^2 dtheta
from theta=0 to theta=pi
4 answers