picture:
http://www.wolframalpha.com/input/?i=plot+y%3D+-x%5E2%2B2x%2B4+%2C+y+%3D-x%2B4
looks like they intersect at (0,4) and((3,1)
(the points satisfy both equations)
area = ∫( -x^2 + 2x + 4 - (-x+4)) dx from 0 to 3
= ∫( -x^2 + 3x ) dx from 0 to 3
= [ -x^3/3 + 3x^2/2 ] from 0 to 3
= (-9 + 27/2
= 9/2
Find the area of the region enclosed by these graphs and the vertical lines x = 0 and x = 3
f(x)=-x^2+2x+4 g(x)=-x+4
1 answer
1 answer