find the area of the region bounded by the graphs of y=x^2 and y=cos(x)

Answer 1

The curves intersect at x = ±0.824
Since the area is symmetric we can just work with one half of it, and double that value:

a = 2∫[0,0.824] cosx - x^2 dx

Answer 2

So the answer would be 1.0947?