Find the area of the region bounded by the curves y = sin x, y = csc^2x, x = pi/4, and x = (3pi)/4.

Answer 1

A quick peek at our problem:
https://www.wolframalpha.com/input/?i=plot+y+%3D+sin+x%2C+y+%3D+csc%5E2x

looks like they intersect at x = π/2 and there is symmetry
so we can take
area = 2∫ (csc^2 x - sinx) dx from π/4 to π/2
recalling that the derivative of cotx = -sec^2 x

= 2[ (- cotx + cosx) ] from π/4 to π/2
= 2 ( (-cot π/2 + cos π/2 - (-cot π/4 + cos π/4) )
= 2( 0 + 0 - (-1 + √2/2) )
= 2(1 - √2/2)
= 2 - √2

Answer 2

Thank you!

Answer 3

This is so easy how do u not know