find the area of the region bounded by the curves f(x)=x-x^3 ; g(x)=x^2-x ; over [0,1]

Answer 1

since f > g on (0,1), the area is just

∫[0,1] (x-x^3)-(x^2-x) dx = 5/12

Answer 2

ty!

Answer 3

i got 5/6?

Answer 4

i used the equation 2x-x^5, is that wrong?

Answer 5

it sure is

(x-x^3)-(x^2-x) = -x^3-x^2+2x

You can't combine x^2 and x^3 to make x^5!! They're added, not multiplied.