Find the area of the region between the curve y^2=4x and the line x=3.

Answer 1

ok, sketch it.

area=INT2ydx from x=0 to 3

area=INT 2*sqrt(4x) dx
= INT 2*2sqrtx dx from x=0 to x^3

= 4*2/3 x^3 over limits
= 8/3 *27

check my work

Answer 2

I sorry but I don't undestand. What would be f(x) and g(x)?

Answer 3

I have no idea what you mean by F(x) or g(x).

Answer 4

I'm sorry. For the equation that I have to use for this it is:

Integral symbol(f(x)-g(x))dx

Answer 5

Sorry I posted into the wrong conversation, please ignore me. Thank you.

Answer 6

f(x)=sqrt(4x) g(x)=-sqrt(4x)

f(x)-g(x)=2*f(x)

Answer 7

Why is g(x)=-sqrt(4x)?

Answer 8

sketch it!

sqrt4x=+- 2sqrtx

Answer 9

Oh I forgot about the ± sign. THANK YOU!!