Asked by Philip

Find the area of the region below y=x^2−2x+3 and above y=9 for 3≤x≤5.

Area =
Answered by PsyDAG
Unclear. Below and above what?

Answered by oobleck
below the parabola and above the line.
Unfortunately, the parabola is only above the line for x > 1+√7 = 3.6
Anyway, when you get things straightened out, the area is clearly just something like
∫[3.6,9] x^2-2x+3 - 9 dx
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