If I understand you correctly, DF is the diameter of a half-circle
radius is clearly 4 units, so that part = π(4^2) = 16π units^2
slope EF = +1, slope DE = -1, so obviously you have a right-angled triangle
Find the length o EF and DE and use the area of a triangle formula to find the area.
Add up the two parts
Find the area of the figure. Round to the nearest tenth if necessary.
D(0,2), E(4, -2), F(8,2)
instead of d and f connecting with a straight line, they are connected with half a circle/curve
The highest point this semicircle part reaches is (4,6)...if im describing it in a confusing way imagine the shape of a sno-cone...its like that
1 answer
1 answer