Find the area of rectangle ABCD , with vertices A(1,7) , B(3,7) , C(3,−4) , and D(1,−4) .(1 point) units2

3 answers

To find the area of the rectangle, we need to find the length of the base and the height of the rectangle.

The base of the rectangle is the distance between points A and B. Using the distance formula, we have:

Base = √[(3-1)^2 + (7-7)^2] = √[2^2] = √4 = 2

The height of the rectangle is the distance between points A and D. Using the distance formula, we have:

Height = √[(1-1)^2 + (7-(-4))^2] = √[11^2] = √121 = 11

Now, we can find the area of the rectangle by multiplying the base and height:

Area = Base x Height = 2 x 11 = 22 units^2

Therefore, the area of rectangle ABCD is 22 square units.
Find the area of rectangle QRST , with vertices Q(−1,7) , R(5,7) , S(5,3) , and T(−1,3) .(1 point) units^2
To find the area of the rectangle QRST, we need to find the length of the base and the height of the rectangle.

The base of the rectangle is the distance between points Q and R. Using the distance formula, we have:

Base = √[(5-(-1))^2 + (7-7)^2] = √[6^2] = √36 = 6

The height of the rectangle is the distance between points Q and T. Using the distance formula, we have:

Height = √[(-1-(-1))^2 + (7-3)^2] = √[4^2 + 4^2] = √[16 + 16] = √32 = 4√2

Now, we can find the area of the rectangle by multiplying the base and height:

Area = Base x Height = 6 x 4√2 = 24√2 units^2

Therefore, the area of rectangle QRST is 24√2 square units.