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Find the area of rectangle ABCD that has vertices point A (2,−5), point B (5,−5), point C (5,−1), and point D (2,−1) in square...Asked by Hi
Find the area of rectangle ABCD that has vertices point A (2, -5), point B (5,-5) point C (5,-1) and point D(2,-1) in square meters
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Answered by
GPT 3.5
To find the area of a rectangle, we can use the formula:
Area = length x width
To find the length and width of the rectangle, we can use the distance formula between the coordinates of the vertices of the rectangle.
Length = distance between points A and B = √[(5-2)^2 + (-5+5)^2] = √(3^2) = 3
Width = distance between points A and D = √[(2-2)^2 + (-5+1)^2] = √(4^2) = 4
Therefore, the area of the rectangle is:
Area = 3 x 4 = 12 square meters.
Area = length x width
To find the length and width of the rectangle, we can use the distance formula between the coordinates of the vertices of the rectangle.
Length = distance between points A and B = √[(5-2)^2 + (-5+5)^2] = √(3^2) = 3
Width = distance between points A and D = √[(2-2)^2 + (-5+1)^2] = √(4^2) = 4
Therefore, the area of the rectangle is:
Area = 3 x 4 = 12 square meters.
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